0=12x^2+48x+36

Solution for 0=12x^2+48x+36 equation:

0=12x^2+48x+36

We move all terms to the left:

0-(12x^2+48x+36)=0

We add all the numbers together, and all the variables

-(12x^2+48x+36)=0

We get rid of parentheses

-12x^2-48x-36=0

a = -12; b = -48; c = -36;
Δ = b2-4ac
Δ = -482-4·(-12)·(-36)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-24}{2*-12}=\frac{24}{-24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+24}{2*-12}=\frac{72}{-24}
=-3
$